The sum of the digits of a two-digit is 15. The tens digit is one more than the units digit. What is the number?

To find the two-digit number, we need to apply the given information that the sum of its digits is 15 and the tens digit is one more than the units digit.

Let's assume the units digit as x. According to the second condition, the tens digit would be x + 1.

The sum of the digits is 15, so we can set up the equation:
x + (x + 1) = 15

Simplifying the equation:
2x + 1 = 15
2x = 15 - 1
2x = 14
x = 14/2
x = 7

Therefore, the units digit is 7, and the tens digit would be x + 1, which is 7 + 1 = 8.

Hence, the number is 87.

These digits yield a sum of 15

9, 6
8, 7

Which pair fits the definition?

Just think of all the pairs that add up to 15:

96
87
78
69

Now which one fits the criteria of your problem?