Table salt, NaCl, and sugar C12H22O11 are accidentally mixed. A 5.50g sample is burned and 3.60g of CO2 is produced. What was the mass percentage of the table salt mixture?
MC12H22O11=342
MCO2=44
C12H22O11+xO2=12CO2+...
Ratio of mass of C12H22O11 to CO2
=342:12*44
=342:484
Mass of C12H22O11 that produces 3.6g CO2
=3.6*(342/484)
=2.544g
Mass ratio NaCl:C12H22O11
=(5.5-2.544):2.544
=2.956:2.544
Calculate mass percentage and reduce to 3 significant figures.
3.60 x (342/12*44) = 3.6 x (342/528) = 2.33 g C12H22O11 to produce 3.60 g CO2.
Then 5.50-2.33 = 3.17 g NaCl and
%NaCl = (3.17/5.50)*100 = ?
57.6 %
3.60 x (342/12*44) = 3.6 x (342/528) = 2.33 g C12H22O11 to produce 3.60 g CO2.
Then 5.50-2.33 = 3.17 g NaCl and
%NaCl = (3.12/5.59)*100 = ?
70.44
To find the mass percentage of the table salt mixture, we need to calculate the mass of NaCl in the sample.
First, we need to determine the moles of CO2 produced. Since the molar mass of CO2 is 44 g/mol, we can calculate the moles using the given mass of CO2:
moles of CO2 = mass of CO2 / molar mass of CO2
moles of CO2 = 3.60 g / 44 g/mol
moles of CO2 ≈ 0.0818 mol
Next, we need to determine the number of moles of carbon present in the CO2. Since each CO2 molecule contains 1 carbon atom, the moles of carbon will be the same as the moles of CO2:
moles of carbon = moles of CO2 ≈ 0.0818 mol
Since each glucose molecule (C12H22O11) contains 6 carbon atoms, we can calculate the moles of glucose produced using the moles of carbon:
moles of glucose = moles of carbon / 6
moles of glucose ≈ 0.0818 mol / 6 ≈ 0.0136 mol
Now, we need to determine the moles of NaCl present in the sample. Since the ratio of CO2 to NaCl in the balanced chemical equation is 1:2, we can use the moles of CO2 to calculate the moles of NaCl:
moles of NaCl = (moles of CO2) / 2
moles of NaCl = 0.0818 mol / 2 ≈ 0.0409 mol
To find the mass of NaCl, we can use its molar mass. The molar mass of NaCl is 58.44 g/mol:
mass of NaCl = moles of NaCl x molar mass of NaCl
mass of NaCl = 0.0409 mol x 58.44 g/mol
mass of NaCl ≈ 2.39 g
Finally, we can calculate the mass percentage of the table salt mixture using the formula:
mass percentage = (mass of NaCl / mass of sample) x 100
mass percentage = (2.39 g / 5.50 g) x 100
mass percentage ≈ 43.45%
Therefore, the mass percentage of the table salt mixture is approximately 43.45%.