After a day of testing race cars, you decide to take your own 1570 kg car onto the test track. While moving down the track at 10.0 m/s, you uniformly accelerate to 34.0 m/s in 10 s. What is the average net force that you have applied to the car during the 10 s interval?
See previous post: Sun,9-22-13,8:57 PM.
To find the average net force, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. The formula can be written as:
F = m * a
Where:
F is the net force (unknown)
m is the mass of the car, which is given as 1570 kg
a is the acceleration, which we can calculate using the formula:
a = (v_f - v_i) / t
Where:
v_f is the final velocity, which is given as 34.0 m/s
v_i is the initial velocity, which is given as 10.0 m/s
t is the time interval, which is given as 10 s
Let's plug in the values and solve for the average net force:
a = (34.0 m/s - 10.0 m/s) / 10 s
a = 24.0 m/s / 10 s
a = 2.4 m/s²
Now we can calculate the average net force:
F = m * a
F = 1570 kg * 2.4 m/s²
F = 3768 N
Therefore, the average net force applied to the car during the 10 s interval is 3768 Newtons.