After a day of testing race cars, you decide to take your own 1570 kg car onto the test track. While moving down the track at 10.0 m/s, you uniformly accelerate to 34.0 m/s in 10 s. What is the average net force that you have applied to the car during the 10 s interval?
a = (V-Vo)/t = (34-10)/10 = 2.4 m/s^2.
Fn = m*a = 1570 * 2.4 = 3768 N.
To find the average net force applied to the car during the 10-second interval, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Initial velocity (u) = 10.0 m/s
Final velocity (v) = 34.0 m/s
Time (t) = 10 s
Mass (m) = 1570 kg
First, we need to calculate the acceleration (a) using the equation of motion:
a = (v - u) / t
Substituting the given values:
a = (34.0 m/s - 10.0 m/s) / 10 s
a = 24.0 m/s / 10 s
a = 2.4 m/s²
Now we can calculate the average net force (F) using Newton's second law:
F = m * a
Substituting the values:
F = 1570 kg * 2.4 m/s²
Calculating:
F = 3768 N
Therefore, the average net force applied to the car during the 10-second interval is 3768 N.
To find the average net force applied to the car during the given interval, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
The mass of the car is given as 1570 kg, and since the car is moving with uniform acceleration, we can determine its acceleration using the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the initial velocity is 10.0 m/s, the final velocity is 34.0 m/s, and the time is 10 s. Plugging these values into the formula, we get:
acceleration = (34.0 m/s - 10.0 m/s) / 10 s
acceleration = 24.0 m/s / 10 s
acceleration = 2.4 m/s²
Now that we have the acceleration, we can calculate the average net force by multiplying the mass of the car by the acceleration:
average net force = mass × acceleration
average net force = 1570 kg × 2.4 m/s²
Calculating this product, the average net force applied to the car during the 10 s interval is:
average net force = 3768 N