If aqueous hydrofluoric acid is reacted with sodium hydroxide, which of the following substances are in the net ionic equation?
1. hydrofluoric acid, hydroxide ion, hydronium ion, fluoride ion, and water
2. hydrofluoric acid, sodium ion, hydroxide ion, and fluoride ion
3. fluoride ion, hydronium ion, and water
4. hydrofluoric acid, hydroxide ion, fluoride ion, and water
5. fluoride ion, hydroxide ion, hydronium
ion, and water
I got a net ionic equation of H + OH --> H2O
NaOH + HF ==> H2O + NaF
OH^- + HF ==> H2O + F^-
To determine which substances are in the net ionic equation for the reaction between aqueous hydrofluoric acid (HF) and sodium hydroxide (NaOH), we need to first write the balanced molecular equation.
The balanced molecular equation for the reaction is:
HF(aq) + NaOH(aq) -> NaF(aq) + H2O(l)
Now, we can break down the molecular equation into its ionic form. In aqueous solutions, compounds dissociate into their constituent ions. The dissociation of HF and NaOH can be represented as follows:
HF(aq) -> H+(aq) + F-(aq)
NaOH(aq) -> Na+(aq) + OH-(aq)
Next, we can identify the spectator ions, which are ions that do not participate in the overall reaction. In this case, the sodium ion (Na+) and the fluoride ion (F-) are spectator ions because they appear on both sides of the equation without undergoing any change.
Now, we can write the net ionic equation by eliminating the spectator ions from the ionic equation. The remaining ions are involved in the net reaction. The net ionic equation for the reaction between HF and NaOH is:
H+(aq) + OH-(aq) -> H2O(l)
So, the substances in the net ionic equation are hydroxonium ion (H+), hydroxide ion (OH-), and water (H2O). Therefore, the correct answer is option 3: fluoride ion, hydronium ion, and water.