physics
posted by Anonymous .
A train slows down as it rounds a sharp horizontal turn, going from 99.0 km/h to 41.0 km/h in the 13.5 s it takes to round the bend. The radius of the curve is 175 m. Compute the acceleration at the moment the train speed reaches 41.0 km/h. Assume the train continues to slow down at this time at the same rate.

change speeds to m/s
then compute the tangential acceleration, changevelocyt/time
now compute the centripetal acceleration
v^2/r
Because these are at right angles, then
accelearation= sqrt(tangential^2+centripetal^2)
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