3^x ∶ x^2-3^x+ 2
I think you mean 3*x or 3x. (3x)+(x^2-3x+2) = x^2 + 2 (3x)-(x^2-3x+2) = -x^2 + 6x - 2 (3x)*(x^2-3x+2) = 3x^3 - 9x^2 + 6x
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