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Given: FG (SEG) bisects BT (SEG)

Prove: BO=50

  • geometry -

    There appears to be insufficient information. Where is O, with respect to BT and FG?

  • geometry -

    It appears to me that O is midway between B and T. If so, then

    7x-6 = 5x+10
    2x = 16
    x = 8

    So, BO = 5*8+10 = 50

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