geometry
posted by
luis
.
Given: FG (SEG) bisects BT (SEG)
BO=7x6
OT=5x+10
Prove: BO=50

geometry 
Graham
There appears to be insufficient information. Where is O, with respect to BT and FG?

geometry 
Steve
It appears to me that O is midway between B and T. If so, then
7x6 = 5x+10
2x = 16
x = 8
So, BO = 5*8+10 = 50