Physics

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A Nordic jumper goes off a ski jump at an angle of 10.0° below the horizontal, traveling 109.0 m horizontally and 44.0 m vertically before landing. (a) Ignoring friction and aerodynamic effects, calculate the speed needed by the skier on leaving the ramp.

  • Physics -

    h = 0.5g*t^2 = 44 m.
    4.9t^2 = 44
    t^2 = 8.98
    t = 3 s. = Time in flight.

    Range = Vo*cos10 * t = 109 m.
    Vo*cos10 * 3 = 109
    Vo = 109/3*cos10 = 36.9 m/s[10o]

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