Logarithms
posted by John .
What's the best way to find Angles using logarithms and viceversa.
Ex: log cot 0.1690 and log sin (25degrees 22min)
log sin (25+22/60)
= log sin 22.3666666667
= sin 0.38053243281
= (0.41960832236)
Is there a simpler way to do these?
I get confused with finding the angles using logarithms

nope. to take the log, ya gotta find the sine first.
Of course, if you have a decent calculator, that means you just have to
enter 22/60+22=
then press deg sin log 
But how can you do the inverse? such as
Log cot B 0.1690 = what angle?
should find the cot first then the log? 
your expression makes no sense.
If you mean
log cot B = 0.1690
then that means
cot B = 10^.1690 = 1.4757
B = cot^{1} 1.4757 = .5955
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