Algebra Homework
posted by Mary .
Find the value of k so that the line containing the points (−5,0) and (k,−2) is parallel to the line
y=(5/9)x−2

First we find the slope of the given points:
m = (y2  y1)/(x2  x1)
Substituting,
m = (0  (2))/(5  k)
m = 2/(5  k)
Then, we get the slope of the given line.
y = (5/9)x − 2
Note that it follows the form y = mx + b, where m is the slope and b is the yintercept. Therefore, its slope = 5/9.
Recall that when two lines are parallel with each other, their slopes are equal. Thus, we equate them:
2/(5  k) = 5/9
2 * 9 = 5(5  k)
18 = 25  5k
5k = 25  18
5k = 43
k = 43/5
Hope this helps~ :3
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