how do i solve this √2x -7+8=11
if the whole (2x-7+8) under square root then we get rid of sqr rt from both sides:
2x-7+8=(11)^2
2x+1=121
2x=120
x=60
if only (2x) is under square root, then:
�ã2x +1=11
�ã2x =10
2x=(10)^2
2x=100
x=50
If you mean
√(2x - 7) + 8 = 11
Then, first we isolate the whole squareroot term on one side of equation:
√(2x - 7) = 11 - 8
√(2x - 7) = 3
Then we square both sides:
2x - 7 = 9
2x = 9 + 7
2x = 16
x = 8
Note that if we're dealing with squareroots, we always check whether the answer can satisfy the original equation, or it is extraneous. Substituting x = 8,
√(2x - 7) + 8 = 11
√(2*8 - 7) + 8 = 11
√(16 - 7) + 8 = 11
√(9) + 8 = 11
3 + 8 = 11
11 = 11
Thus x is equal to 8.
Hope this helps~ :3
To solve the equation √(2x) - 7 + 8 = 11, you need to follow these steps:
Step 1: Combine like terms
Add 7 and 8 on the left side of the equation to simplify the equation:
√(2x) - 7 + 8 = √(2x) + 1
Step 2: Isolate the square root term
To solve for x, we need to isolate the square root term on one side of the equation. To do this, subtract 1 from both sides of the equation:
√(2x) = 11 - 1
√(2x) = 10
Step 3: Square both sides
To eliminate the square root, square both sides of the equation:
(√(2x))^2 = 10^2
2x = 100
Step 4: Solve for x
Divide both sides of the equation by 2 to solve for x:
2x/2 = 100/2
x = 50
Therefore, the solution to the equation √(2x) - 7 + 8 = 11 is x = 50.