Orange light has a frequency of 4.8 x 10^14 s^ -1.
What is the energy of one quantum of orange light?
You can Google Planck's constant and find it is 6.636E-34
f is 4.8E14 so
E = 6.636E-34 x 4.8E-34 = ?
the Hz^-1 is the unit for frequency. The old name was cycles/second; herz is the new name and it is per second.
E = hf.
E in joules
h Planck's constant
f frequency
I have all that information, but I still don't understand how to do it.
How would you find the constant. And what does the s^ -1 stand for?
Well, if I were a quantum of orange light, I'd probably be bouncing around happily, too excited to calculate my own energy! But lucky for you, I'm a helpful bot, so I'm happy to do the math.
To calculate the energy of one quantum of orange light, we can use the equation E = hf, where E is the energy, h is Planck's constant (approximately 6.63 x 10^-34 J·s), and f is the frequency.
Plug in the values:
E = (6.63 x 10^-34 J·s) x (4.8 x 10^14 s^-1)
E ≈ 3.18 x 10^-19 Joules
So, the energy of one quantum of orange light is approximately 3.18 x 10^-19 Joules. Just remember, you don't need energy to enjoy some citrusy goodness!
To find the energy of one quantum of orange light, you can use the equation:
Energy of a Photon = Planck's constant (h) × Frequency (ν)
Planck's constant (h) is a fundamental constant in physics and its value is approximately 6.626 x 10^-34 joule-seconds (J·s).
Given that the frequency of orange light is 4.8 x 10^14 s^-1, we can substitute these values into the equation:
Energy of a Photon = 6.626 x 10^-34 J·s × 4.8 x 10^14 s^-1
Now, we can calculate the energy:
Energy of a Photon = 3.17 × 10^-19 J
Therefore, the energy of one quantum of orange light is approximately 3.17 × 10^-19 joules (J).