When a positive integer z is divided by 9, the remainder is 2. what is the remainder when 4z is divided by 6?
Venus -- you appear to be dumping your homework here.
Please show us what you know about these problems before you post a new question.
Ms. Sue,
z/9 = x remainder 2
4z/6 = what is the remainder?
say if z = 20, then 20/9 = 2 remainder 2
so, (4 x 20)/6 = 13 remainder 2
I got the answer as 2.
But the answer key on practice test says 3. so I was asking for your help.
Thank you !
To determine the remainder when 4z is divided by 6, we need to find the remainder when z is divided by 6.
Given that z leaves a remainder of 2 when divided by 9, we can write z as:
z = 9n + 2 (where n is an integer)
Now, let's substitute this value of z into the expression for 4z:
4z = 4(9n + 2) = 36n + 8
To find the remainder when 4z is divided by 6, we need to divide 36n + 8 by 6.
Dividing 36n by 6 gives us 6n, and dividing 8 by 6 gives us a remainder of 2.
Therefore, the remainder when 4z is divided by 6 is 2.