Heat energy is added to a 325 g block of nickel, and the temperature increases from 23 degrees celsius to 51 degrees celsius. If the same amount of heat was added to the same mass of water at the same temperature, what would the water's final temperature be?

q = mass Ni x specific heat Ni x (Tfinal-Tinitial) = ?

Look up the specific heat Ni, substitute in the above and solve for q. Then substitute into the below.
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)

To solve this problem, we can use the concept of specific heat capacity. The specific heat capacity is the amount of heat energy required to raise the temperature of a substance by a certain amount. The formula for calculating the heat energy transferred is:

Q = mcΔT

where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

In this case, we have a 325 g block of nickel, and the temperature increases from 23°C to 51°C. The specific heat capacity of nickel is 0.444 J/g°C.

Using the formula, we can calculate the heat energy transferred for the nickel:

Q = (325 g) x (0.444 J/g°C) x (51°C - 23°C)

Q = 8256 J

The same amount of heat energy is added to the same mass of water, but at the same temperature. We need to find the final temperature of the water.

We can rearrange the formula as:

Q = mcΔT

and solve for ΔT:

ΔT = Q / mc

The specific heat capacity of water is 4.18 J/g°C.

ΔT = (8256 J) / ((325 g) x (4.18 J/g°C))

ΔT = 6.004°C

To find the final temperature of the water, we add the change in temperature to the initial temperature:

Final temperature = 23°C + 6.004°C

Final temperature ≈ 29.004°C

Therefore, the approximate final temperature of the water would be 29.004°C.