posted by Janae .
3x^2 + 8 = -4
no solution. I suspect a typo. Assuming an 8x, we have
(x+2)(3x+2) = 0
there isn't any 8x it just say solve for x
well, shoot. Then just subtract 8 from both sides to get
3x^2 = -12
x^2 = -4
there is no real solution, since x^2 is never negative for real x.
If you allow complex solutions, then x = 2i or -2i. I believe this is from Algebra I, and should not be posing a difficulty for someone in Pre-Cal...