You have a 1 ml solution containing 100 uM Ethanol, and 1 mM NAD+. You then add 1 mg of alcohol dehydrogenase. Assume all of the ethanol gets converted to acetaldehyde
. a) What will the final concentration of NADH be in the solution?
To find the final concentration of NADH in the solution, we need to calculate the amount of NADH produced when all the ethanol is converted to acetaldehyde.
First, let's determine the moles of ethanol present in the 1 ml solution:
Amount of ethanol = Concentration of ethanol x Volume of solution
Amount of ethanol = 100 μM x 1 ml = 0.1 μmoles
Since ethanol is converted to acetaldehyde through the action of alcohol dehydrogenase and NAD+, we need to use the stoichiometry of the reaction to determine the amount of NADH produced.
The balanced equation for the reaction is:
Ethanol + NAD+ → Acetaldehyde + NADH
According to the equation, 1 mole of ethanol is converted to 1 mole of acetaldehyde and produces 1 mole of NADH.
Therefore, the moles of NADH produced will be equal to the moles of ethanol used:
Moles of NADH = Moles of ethanol = 0.1 μmoles
Now, let's convert the moles of NADH to concentration:
Concentration of NADH = Moles of NADH / Volume of solution
Concentration of NADH = 0.1 μmoles / 1 ml = 0.1 μM
So, the final concentration of NADH in the solution will be 0.1 μM.