A quadrilateral has interior angles with degree measures of 63, 4s, 5s and 2s. What is the angle measure, in degrees, of the largest angle of the quadrilateral?

Note that the sum of interior angles of a quadrilateral is equal to 360 degrees. Therefore,

63 + 4s + 5s + 2s = 360
We then find the value of s:
4s + 5s + 2s = 360 - 63
11s = 297
s = 27
Finally, we solve for the remaining angles,
4s = 4*27 = 108 degrees
5s = 5*27 = 135 degrees
2s = 2*27 = 54 degrees

Therefore, the largest angle measures 135 degrees.

Hope this helps~ :3

To find the angle measure of the largest angle of the quadrilateral, you need to compare the degree measures of the interior angles. Let's start by labeling the angles:

Let Angle A = 63 degrees
Let Angle B = 4s degrees
Let Angle C = 5s degrees
Let Angle D = 2s degrees

Since a quadrilateral has a total of 360 degrees (sum of all interior angles), we can write an equation to solve for the value of s:

63 + 4s + 5s + 2s = 360

Combine like terms:

63 + 11s = 360

Subtract 63 from both sides of the equation:

11s = 297

Divide both sides by 11 to solve for s:

s = 27

Now that we know the value of s, we can substitute it back into the equation to find the angle measures:

Angle B = 4s = 4 * 27 = 108 degrees
Angle C = 5s = 5 * 27 = 135 degrees
Angle D = 2s = 2 * 27 = 54 degrees

Now we can compare the angle measures. The largest angle is Angle C, which measures 135 degrees.

Therefore, the angle measure of the largest angle in the quadrilateral is 135 degrees.