For the reaction 2C6H6+15O2 =12CO2+6H2O, what is the maximum amount of CO2 which could be formed from 5.12 g of C6H6 and 12.28 g of O2?
This is a limiting reagent problem. I now that because amounts are given for BOTH reactants.
Convert 5.12g C6H6 to mols. mols = grams/molar mass.
Do the same for 12.28g O2.
Using the coefficients in the balanced equation, convert mols C6H6 to mols CO2.
Do the same for mols O2 to mols CO2.
It is likely that the two values for mols CO2 will not agree which means one of them is wrong; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Now convert mols CO2 to grams. g = mols x molar mass.
Post your work if you get stuck.
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To find the maximum amount of CO2 that could be formed from the given amounts of C6H6 and O2, we need to use the concept of stoichiometry. Stoichiometry allows us to determine the amounts of reactants and products in a chemical reaction.
1. Start by calculating the number of moles of C6H6 and O2 using their respective molecular weights. The molecular weight of C6H6 (benzene) is 78.11 g/mol, and the molecular weight of O2 is 32.00 g/mol.
Number of moles of C6H6 = mass of C6H6 (g) / molecular weight of C6H6 (g/mol)
= 5.12 g / 78.11 g/mol
= 0.0657 mol (rounded to four decimal places)
Number of moles of O2 = mass of O2 (g) / molecular weight of O2 (g/mol)
= 12.28 g / 32.00 g/mol
= 0.384 mol (rounded to three decimal places)
2. Now, we need to determine the stoichiometric ratio between C6H6 and CO2. From the balanced chemical equation, we know that 2 moles of C6H6 react to produce 12 moles of CO2.
2C6H6 + 15O2 → 12CO2 + 6H2O
So, the mole ratio between C6H6 and CO2 is 2:12, which simplifies to 1:6.
3. Using the mole ratio, calculate the maximum moles of CO2 that can be formed from the given amount of C6H6.
Maximum moles of CO2 = moles of C6H6 × moles of CO2 / moles of C6H6
= 0.0657 mol × 12/2
= 0.3931 mol (rounded to four decimal places)
4. Finally, convert the moles of CO2 to grams using its molecular weight, which is 44.01 g/mol.
Maximum mass of CO2 = moles of CO2 × molecular weight of CO2 (g/mol)
= 0.3931 mol × 44.01 g/mol
= 17.29 g (rounded to two decimal places)
Therefore, the maximum amount of CO2 that could be formed from 5.12 g of C6H6 and 12.28 g of O2 is 17.29 g.