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If the water had lost 12000 joules and the calorimeter gained 1300 joules as the temperature of both rock and calorimeter increased from 22°C to 73°C and the mass of rock in the calorimeter was 189 grams, what is the specific heat, c, of the rock material?

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    If the water had lost 12000 joules and the calorimeter gained 1300 joules, then the rock gained the difference in energy.

    c = ∆E/m∆T = (12000-1300)/(73-22) [J/g·K]

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