Algebra, HELP IM CLUELESS

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Eureka is 16 years younger than Renton. In 3 years Renton will be twice as old as Eureka. How old are they now?

Eureka's Age:
Renton's Age:

  • Algebra, HELP IM CLUELESS -

    E = Eureka's Age

    R = Renton's Age


    E = R - 16


    In 3 years Renton will be R + 3

    Eureca will be E + 3


    In 3 years Renton will be twice as old as Eureka.

    This mean :

    R + 3 = 2 ( E + 3 )


    R + 3 = 2 ( R - 16 + 3 )

    R + 3 = 2 ( R - 13 )

    R + 3 = 2 R - 26 Add 26 to both sies

    R + 3 + 26 = 2 R - 26 + 26

    R + 29 = 2 R Subtract R to both sides

    R + 29 - R = 2 R - R

    29 = R

    R = 29


    E = R - 16

    E = 29 - 16

    E = 13


    Eureka's Age = 13

    Renton's Age = 29


    Proof :

    In 3 years Renton will be 32

    Eureca will be 16

    32 / 16 = 2

    Renton will be twice as old as Eureka.

  • Algebra, HELP IM CLUELESS -

    Let y be Eureka's age in years.
    Let x be Renton's age in years.

    So:
    y = x-16
    2(y+3) = x+3

    Rearrange to express x as a function of y.
    x = y + 16
    x = 2y + 3

    Eliminating x by equating:
    y + 16 = 2y +3
    => y = 13

    Substituting back to obtain x.
    x = 13 + 16
    => x = 29

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