Suppose you have two 100mL graduated cylinders. In each cylinder, there is 36.0mL of water. You also have two cubes: one is lead, and the other is aluminum. Each cube measures 3.00cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in the cylinder with the lead cube?

Don't be distracted by the different materials. The density of the solid is irrelevant to this.

The volume of water displaced will be the volume of the object displacing it. That is all.

Ergo: What is the volume of a cube measuring 3.00[cm] on each side?

volume Pb cube = 3cm x 3 cm x 3 cm = ? cc

36.0 cc water level + ? cc occupied by Pb cube = new water level.

All of that information about the second cylinder with water and the aluminum cube is superfluous information.

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To determine the new water level in the cylinder with the lead cube, we need to consider the volume of the lead cube and how it displaces the water in the cylinder.

First, let's calculate the volume of the lead cube. Since each side of the cube measures 3.00 cm, the volume can be calculated using the formula:

Volume = length * width * height = (3.00 cm)^3 = 27.00 cm^3

Now, let's determine how much water the lead cube displaces. Since the water level in the graduated cylinder was initially at 36.0 mL and the volume of the lead cube is 27.00 cm^3, we can convert this to milliliters using the fact that 1 cm^3 is equal to 1 mL:

Displaced Water = Volume of Lead Cube = 27.00 mL

Therefore, the lead cube displaces 27.00 mL of water. So, the new water level in the cylinder with the lead cube will be:

New Water Level = Initial Water Level - Displaced Water = 36.0 mL - 27.00 mL = 9.0 mL