An autos velocity increases uniformly from 6m/s to20m/s while covering 70m.find the acceleration and the time taken.
Tangina di ko gets
To find the acceleration and the time taken, we can use the kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity
u = initial velocity
s = displacement
a = acceleration
We are given:
u = 6 m/s
v = 20 m/s
s = 70 m
First, let's find the acceleration:
Rearranging the equation, we have:
(v^2 - u^2) = 2as
Substituting the given values, we get:
(20^2 - 6^2) = 2a * 70
(400 - 36) = 140a
364 = 140a
a = 364 / 140
a ≈ 2.6 m/s^2
So, the acceleration is approximately 2.6 m/s^2.
Now, let's find the time taken:
We can use another kinematic equation:
v = u + at
Substituting the given values, we have:
20 = 6 + 2.6t
Rearranging the equation, we get:
2.6t = 20 - 6
2.6t = 14
t = 14 / 2.6
t ≈ 5.38 seconds
So, the time taken is approximately 5.38 seconds.
5 and 3
Not clear
s = 6t + 1/2 at^2
v = 6+at
20 = 6+at
at = 14
70 = 6t+7t = 13t
t = 70/13
a = 14/t = 14*13/70 = 13/5
with appropriate units