Geometry/algebra 1
posted by Anonymous .
Use the given area A of the rectangle to find the value of x. Then give the dimensions of the rectangle.
A=91m^2
A=L•W
L=(2x+3)m
W=(x+2)m
91m^2=(2x+3)m•(x+2)m
91=(x+2)(2x+3)
Now what?

Set the equation equal to 0:
2x^2 + 4x + 3x + 6  91 = 0
2x^2 + 7x  85 = 0
Factor:
(2x + 17) (x  5) = 0
Set the factors equal to 0:
2x + 17 = 0; x = 17/2
x  5 = 0; x = 5
You can't have a negative number for this problem, so use x = 5 for the value of x.
I'll let you take it from here to determine the dimensions of the rectangle.