Solve for s
пr(s+r)
Solve for a
S= a(1-r^n)/1-r
In the first, the word "solve" implies an equals sign, I don't see one.
In the second, I am assuming n is a fixed number.
(1-r)S=a-ar^n
ar^n+rS=aS-a check that.
Now solutions to that depends on several things.
when n>=3, it has specific solution methods only for specific values. At n=2, the quadratic equation is very famous. At 1, any Algebra student should be able to handle it.
The PI symbol in the first bothers me you might be studying something very advance, normally reserved for upper college students. Look the PI symbol in Math, it is more than 3.14159...
http://en.wikipedia.org/wiki/Pi_%28letter%29
Since we're not solving for r, the polynomial stuff doesn't matter.
(1-r)S = a(1-r^n)
a = (1-r)S/(1-r^n)
To solve for s in the equation пr(s+r), we can follow the steps below:
1. Distribute the пr to both terms inside the parentheses:
пr(s+r) = пrs + пr^2
2. Set the equation equal to a value or another expression if provided. If the equation is already set equal to something, you can skip this step.
3. If the equation is not set equal to something, the solution is simply пrs + пr^2.
To solve for a in the equation S = a(1 - r^n) / (1 - r), we can follow the steps below:
1. Multiply both sides of the equation by (1 - r) to eliminate the fraction:
S(1 - r) = a(1 - r^n)
2. Distribute the terms on the left side of the equation:
S - Sr = a(1 - r^n)
3. Divide both sides of the equation by (1 - r):
(S - Sr) / (1 - r) = a
Therefore, the solution for a is (S - Sr) / (1 - r).