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posted by nami .
Let ABC be a triangle.Draw median AD on BC.Draw median AE of triangle ABD on BD.Take a point on side AB say F and join CF. Now from D make a line parallel to CF such that the line cuts AB at G. Note G lies between F and B. AD intersect CF and P. AE intersect GD at H. So BD=DC Given AP=PD BE=ED CF parallel to GD. Find [AHD]/[ABC]

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