Water flows into a swimming pool at the rate

of 5
.
25 gal
/
min.
If the pool dimensions are 33
.
8 ft wide, 40 ft
long and 11
.
1 ft deep, how long does it take to
fill the pool? (1 gallon = 231 cubic inches)
Answer in units of min

time=volume/rate

1 gallon=231/(12x12x12) cubic feet, or you should MEMORIZE this

7.48 USgallons/cubic ft.

To find the time it takes to fill the pool, we need to calculate the volume of the pool and divide it by the rate at which water flows into the pool.

First, let's convert the dimensions from feet to inches since the conversion factor for gallons is given in cubic inches.

- Width: 33.8 ft = 33.8 ft * 12 in/ft = 405.6 inches
- Length: 40 ft = 40 ft * 12 in/ft = 480 inches
- Depth: 11.1 ft = 11.1 ft * 12 in/ft = 133.2 inches

Next, let's calculate the volume of the pool in cubic inches:

Volume = Length * Width * Depth
Volume = 480 inches * 405.6 inches * 133.2 inches

Now let's convert the unit of volume from cubic inches to gallons:

Volume(gal) = Volume(cubic inches) / Conversion factor
Volume(gal) = Volume(cubic inches) / 231 cubic inches/gallon

Finally, we can calculate the time it takes to fill the pool:

Time = Volume(gal) / Flow rate(gal/min)

Let's plug in the values and calculate the time:

Time = (480 inches * 405.6 inches * 133.2 inches) / (231 cubic inches/gallon * 5.25 gal/min)

After calculating this expression, we get the answer in units of minutes.