Using only the digits 2,3,5 and 7 complete the following problems below.
1.Name two things that the numbers 2,3,5,7 have in common
1.All prime numbers
2.What is the smallest possible number that can be written using each of these digits only once?
2357?
3.Using the 7 in the hundreth's place write the largest possible number below.(Make sure to use each of the remaining digits only once)
57.32
4.Using each of the numbers above only once, write three numbers whose value is greater than 2.5 but less than 3.
2.537
2.753
2.357
1. Also they are one-digit numbers.
2. Right.
3. Wrong. Which is the hundredths place?
4. The first two are right. Your third answer is wrong.
3. 75.32
4. 2.735
3. Hundredths are to the right of the decimal point. Study this chart.
http://www.enchantedlearning.com/math/decimals/placevalue/
4. Right.
1. To determine what the numbers 2, 3, 5, and 7 have in common, we need to analyze their properties. One property that all these numbers possess is being prime numbers. A prime number is a positive integer greater than 1 that has no positive divisors other than 1 and itself. By checking the divisibility of these numbers, we can see that neither 2, 3, 5, nor 7 have any divisors other than 1 and themselves, meeting the definition of prime numbers.
2. To find the smallest possible number using each of the digits 2, 3, 5, and 7 only once, we can arrange them in ascending order. Starting with the smallest digit, which is 2, then moving to 3, 5, and finally 7, we get the number 2357. This is the smallest possible number that can be formed using these digits without repetition.
3. For this problem, we need to arrange the digits 2, 3, 5, and 7 to create the largest possible number below 1000, using each digit only once. Since the 7 needs to be in the hundredth's place, we can place it there first. Then, arranging the remaining digits in descending order, we get 7532. Therefore, the largest possible number below 1000 is 753.2.
4. To find three numbers greater than 2.5 but less than 3 using the given digits, we can start by fixing the decimal point at the tenth's place. Then, arrange the remaining three digits, 2, 3, and 5, in different orders. This yields the following numbers greater than 2.5 but less than 3: 2.537, 2.753, and 2.357.