physics

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I need to calculate the horizontal, vertical and resultant velocity of a ball thrown a distance of 8.23m in a time of 1.73sec (assuming the ball lands at the same height from which it is thrown). The angle of the throw is unknown.

Please help!

  • physics -

    u = 8.23/1.73 = 4.76 m/s horizontal speed
    in air for 1.73 s
    so going up for .865 s
    v = Vi - g t
    0 = Vi - 9.81(.865)
    so
    Vi = 8.49 m/s initial speed up

    for resultant initial speed
    s^2 = u^2 + Vi^2
    = 22.66 + 72.1 = 94.7
    so
    s = 9.73 m/s

    T = angle to horizontal
    sin T = 8.49/9.73
    T = 60.8 degrees above horizontal

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