1.
_____C2H6(g) + _____O2(g) ---> _____H2O(g) + _____CO2(g)
Is my answer right?
= 2C2H12(g)+2O7---> H12O6+2C2O8
No, your answer is not correct. Let's go through the process of balancing the chemical equation step by step.
First, let's count the number of atoms on each side of the equation:
On the left side:
C: 2 atoms
H: 6 atoms
O: 2 atoms
On the right side:
H: 14 atoms
O: 14 atoms
C: 4 atoms
The equation you provided has different numbers of atoms on each side, so it is unbalanced.
To balance the equation, you need to adjust the coefficients in front of each compound until the number of atoms on both sides of the equation are equal.
Let's start with balancing the carbon atoms:
On the left side, we have 2 carbon atoms in C2H6, and on the right side, we have 1 carbon atom in CO2. To balance the carbon atoms, we need to put a coefficient of 2 in front of CO2.
The new equation becomes:
C2H6(g) + _____O2(g) ---> _____H2O(g) + 2CO2(g)
Next, let's balance the hydrogen atoms:
On the left side, we have 6 hydrogen atoms in C2H6 and none on the right side. To balance the hydrogen atoms, we need to put a coefficient of 3 in front of H2O.
The updated equation becomes:
C2H6(g) + _____O2(g) ---> 3H2O(g) + 2CO2(g)
Finally, let's balance the oxygen atoms:
On the left side, we have 2 oxygen atoms in O2 and on the right side, we have 6 oxygen atoms in 3H2O and 4 oxygen atoms in 2CO2. To balance the oxygen atoms, we need to put a coefficient of 7/2 in front of O2. However, it is not common to have a fractional coefficient, so we can multiply the entire equation by 2 to eliminate the fraction.
The fully balanced equation becomes:
2C2H6(g) + 7O2(g) ---> 6H2O(g) + 4CO2(g)
So the correct balanced equation is:
2C2H6(g) + 7O2(g) ---> 6H2O(g) + 4CO2(g)