) Horizontal beam supported on both ends - square profil 100 × 100 × 5, length is 800 mm.It is bent by the force in the middle of the beam by 0.2 mm. To achieve approximately half of the value of deflection,you will use the beam:

To determine the required dimensions of the beam to achieve approximately half of the given deflection, we need to use the formula for the deflection of a horizontally supported beam under a central load.

The formula for the deflection of a beam under a central load is:

δ = (F * L^3) / (48 * E * I)

Where:
δ = deflection
F = force applied at the center of the beam
L = length of the beam
E = modulus of elasticity of the material
I = moment of inertia of the beam's cross-sectional shape

In this case, we are given the force and the deflection and need to find the beam dimensions that will provide half of the given deflection. So, we can rearrange the formula to solve for the moment of inertia (I) as follows:

I = (F * L^3) / (48 * E * δ)

To find the required beam dimensions, we need to know the material's modulus of elasticity (E). Additionally, the shape and dimensions of the beam cross-sections are required to calculate its moment of inertia.

Once these values are known, we can substitute them into the formula to calculate the moment of inertia (I). From there, we can determine the dimensions that will provide half of the given deflection.

Please provide the modulus of elasticity of the material and the cross-sectional shape and dimensions of the beam to proceed with the calculation.