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How many moles of LiF would be required to produce a 2.5 M solution with a volume of 10.5 L?

10.5L/(2.5moles/L) = 4.2 moles

To find the number of moles of LiF required to produce a 2.5 M solution with a volume of 10.5 L, we can use the formula:

Molarity (M) = Moles (mol) / Volume (L)

Rearranging the formula, we get:

Moles (mol) = Molarity (M) × Volume (L)

Given that the molarity is 2.5 M and the volume is 10.5 L, we can substitute these values into the formula:

Moles (mol) = 2.5 M × 10.5 L

Multiplying the molarity and the volume, we get:

Moles (mol) = 26.25 mol

Therefore, 26.25 moles of LiF would be required to produce a 2.5 M solution with a volume of 10.5 L.