calculus

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how would you solve a problem like this for X:

(1/3=(3^2x+2)

  • calculus -

    I assume you meant

    1/3 = 3^(2x+2)
    then , since we can make the bases the same ....

    3^-1 = 3^(2x+2)
    2x+2 = -1
    2x = -3
    x = -3/2

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