calculus
posted by Brittany .
how would you solve a problem like this for X:
(1/3=(3^2x+2)

I assume you meant
1/3 = 3^(2x+2)
then , since we can make the bases the same ....
3^1 = 3^(2x+2)
2x+2 = 1
2x = 3
x = 3/2
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