1. What is the mass of the 3.7 mol PbO2?
A. 884 g PbO2
B. 65 g PbO2
C. 0.15 g PbO2
D. 825 g PbO2
I honestly have no guess for this one. Can anyone tell me how to do it?
g = mols x molar mass
the temperature of a substance as its heat of fusion is added to melt the substance
A- 884 g pbo2
To find the mass of a substance, you need to multiply the number of moles by the molar mass of that substance. In this case, let's calculate the molar mass of PbO2 and then multiply it by the given number of moles.
The molar mass of PbO2 can be found by adding up the atomic masses of its constituent elements.
The atomic mass of Pb (Lead) is 207.2 g/mol, and the atomic mass of O (Oxygen) is 16.0 g/mol. Since there are two oxygen atoms in PbO2, we multiply the atomic mass of oxygen by 2.
Therefore, the molar mass of PbO2 = (207.2 g/mol of Pb) + (16.0 g/mol of O * 2) = 207.2 g/mol + 32.0 g/mol = 239.2 g/mol.
Now, to find the mass of 3.7 moles of PbO2, we multiply the number of moles (3.7 mol) by the molar mass (239.2 g/mol):
Mass = 3.7 mol * 239.2 g/mol = 884.24 g PbO2 (approximately)
So, the correct answer is A. 884 g PbO2.