i am a 2 digit decimal , the sum of my digit is 12. if you divide me by a certain number the quotient is 37. who am i?

caca

katy, that's hexadecimal, not decimal! :-)

To solve this problem, we need to find a 2-digit decimal number whose digits add up to 12 and, when divided by a certain number, gives a quotient of 37.

Let's start by listing all the possible 2-digit decimal numbers whose digits add up to 12: 39, 48, 57, 66, 75, 84, and 93.

Now, we need to figure out which of these numbers, when divided by a certain number, gives a quotient of 37. We can do this by dividing each number by different divisors until we find the one that gives a quotient of 37.

Let's begin with the first number, 39. We divide it by different numbers:

39 ÷ 1 = 39
39 ÷ 2 = 19.5
39 ÷ 3 = 13
39 ÷ 4 = 9.75
39 ÷ 5 = 7.8
39 ÷ 6 = 6.5
39 ÷ 7 = 5.57...
39 ÷ 8 = 4.875
39 ÷ 9 = 4.33...
39 ÷ 10 = 3.9
39 ÷ 11 = 3.54...
39 ÷ 12 = 3.25
39 ÷ 13 = 3
39 ÷ 14 = 2.7857...
39 ÷ 15 = 2.6
.
.
.

Continuing this process for the other numbers, we find that none of them gives a quotient of 37. Therefore, there is no 2-digit decimal number whose digits sum up to 12 and divided by a certain number gives a quotient of 37.

Hence, the answer to this problem is that there is no such number that satisfies all the given conditions.