write the missing digit....
[ ] 6 [ ]
x 4 [ ] 5
-----------------
1 [ ] 4 [ ]
[ ] 0 [ ]
1[ ]7 [ ]
------------------
[ ]1[ ]0 [ ] 5
1345 * 807 = 117015
Oops.
269 * 435 = 117015
To find the missing digits, let's solve the multiplication problem step-by-step.
First, let's multiply the units place of the top number by the units place of the bottom number:
6 x 5 = 30 (Since there is a carryover, we'll write down 0 and carryover 3)
Next, let's multiply the units place of the top number by the tens place of the bottom number:
6 x 4 = 24
Now, let's multiply the tens place of the top number by the units place of the bottom number:
(Which digit is missing?)
Finally, let's multiply the tens place of the top number by the tens place of the bottom number:
(Which digit is missing?)
Once you find which digits are missing, please provide that information so I can assist you further.
To find the missing digits, we can solve the multiplication problem step by step. Let's start from the rightmost column and move towards the left:
First, we multiply 5 by 4, which gives us 20. So, the unit's digit of the product is 0, and we write it in the bottom row under the line.
Next, we multiply 4 by 6, which gives us 24. Since the previous step gave us a unit's digit of 0, we need to carry the tens place value over here. So, we have a carry of 2. We write the unit's digit, 4, in the bottom row under the line.
Moving to the left and looking at the next column, we multiply 5 by 6, which gives us 30. Since we had a carry of 2 from the previous step, we add it to the product. So, we get 30 + 2 = 32. The ten's place value of 32 is 3, and the unit's digit is 2. We write down 2 in the bottom row under the line.
Continuing further to the left, we multiply 5 by the hundreds place digit, which is unknown (denoted as [ ]). Let's similarly denote the missing digit as X for now. We can set up an equation to find X.
5 * [ ] = 2X
Since we already calculated that the unit's digit of the product is 2, we know that the value of X should result in a unit's digit of 2 when multiplied by 5.
The possible values for X are 4, 8, and 9. By trying each value, we find that 9 * 5 = 45, which has a unit's digit of 5. Therefore, the missing digit is 9.
Finally, we can complete the multiplication problem:
[9] 6 [ ]
x 4 [ ] 5
-----------------
1 [ ] 4 [ ]
[ ] 0 [ ]
1[ ]7 [ ]
------------------
[ ]1[ ]0 [ ] 5