math

posted by .

using the formula W=33-(10.45 + 10sqrtv-v (33- T)/22 how do I find the wind chill temperatue for the following given: T=)c, V=15m/sec, T= -10C, V=20m/sec?

  • math -

    I'd say, just plug in the numbers:

    W = 33-(10.45 + 10√v - v (33- T)/22
    = 33 - (10.45 + 10√20 - 20(33-(-10))/22

    The only problem I see is that your parentheses are unbalanced. Fix that and just evaluate the expression.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Integration

    Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct?
  2. Calculus 12th grade (double check my work please)

    2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents …
  3. Calculus 12th grade (double check my work please)

    1.) which of the following represents dy/dx when y=e^-2x Sec(3x)?
  4. Calculus PLEASE check my work ,

    1.) which of the following represents dy/dx when y=e^-2x Sec(3x)?
  5. calculus (check my work please)

    Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] …
  6. Math

    The formula W = 35.74 + 0.6215T - 35.75V^4/25 + 0.4275TV^4/25 relates the wind chill temperature W to the air temperature T in degrees Fahrenheit and the wind speed V in miles per hour. Use a calculator to find the wind chill to the …
  7. physics

    A ball is thrown upward. Its initial vertical component of velosity is 30m/s and its initial horizontal component of velosity is 20m/s. What is the ball's speed 2 s later?
  8. Algebra 2

    Using data for the effect of temperature and wind on an exposed face, the National Weather Service uses the following formula, Wind Chill Index = 35.74 + 0.6215𝑇 − 35.75𝑉!.!" + 0.4275𝑇𝑉!.!" 𝑇 …
  9. Math

    Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the …
  10. Math

    starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. The distance between the bicycle and the checkpoint is given by the equation …

More Similar Questions