using the formula W=33-(10.45 + 10sqrtv-v (33- T)/22 how do I find the wind chill temperatue for the following given: T=)c, V=15m/sec, T= -10C, V=20m/sec?
I'd say, just plug in the numbers:
W = 33-(10.45 + 10√v - v (33- T)/22
= 33 - (10.45 + 10√20 - 20(33-(-10))/22
The only problem I see is that your parentheses are unbalanced. Fix that and just evaluate the expression.
To find the wind chill temperature using the given formula W = 33 - (10.45 + 10√v - v(33 - T)/22), you need to substitute the given values of T and V into the formula and calculate the result.
Let's substitute the first set of values, T = 0°C and V = 15 m/sec, into the formula:
W = 33 - (10.45 + 10√15 - 15(33 - 0)/22)
First, let's simplify the expression within the parentheses:
10√15 = 10 × √15 ≈ 38.73
15(33 - 0)/22 = 15 × 33/22 ≈ 22.5
Now, substitute the simplified values back into the equation:
W = 33 - (10.45 + 38.73 - 22.5)
Next, calculate the expression within the parentheses:
10.45 + 38.73 - 22.5 ≈ 26.68
Finally, substitute this value back into the equation:
W = 33 - 26.68 ≈ 6.32
Therefore, the wind chill temperature for T = 0°C and V = 15 m/sec is approximately 6.32°C.
Now let's calculate the wind chill temperature for the second set of values, T = -10°C and V = 20 m/sec. Following the same steps:
W = 33 - (10.45 + 10√20 - 20(33 - (-10))/22)
Simplifying within the parentheses:
10√20 = 10 × √20 ≈ 44.72
20(33 - (-10))/22 = 20 × 43/22 ≈ 38.18
Substituting the values back into the equation:
W = 33 - (10.45 + 44.72 - 38.18)
Calculating the expression within the parentheses:
10.45 + 44.72 - 38.18 ≈ 16.99
Finally, substitute this value back into the equation:
W = 33 - 16.99 ≈ 16.01
Therefore, the wind chill temperature for T = -10°C and V = 20 m/sec is approximately 16.01°C.