If m <DCE=4x+15 and m<ECF=6X-5 ,find m<DCE
Álgebra if a supplement of an angle has a measure 78 less than the measure of the angle,what are the measures of the ángeles?
can you show the angle to get the answer
To find the measure of angle DCE, you need to substitute the values of the angles ECF and x into the expression for m<DCE.
m<DCE = 4x + 15
Given that m<ECF = 6x - 5, you can substitute this value into the expression for m<DCE:
m<DCE = 4(6x - 5) + 15
Now, simplify the expression:
m<DCE = 24x - 20 + 15 = 24x - 5
Therefore, the measure of angle DCE is 24x - 5.
find the measure of angle DCE.
The angles are assumed to be complimentary(sum=90o).
DCE + ECF = 90o
4x+15 + 6x-5 = 90
10x + 10 = 90
10x = 80
X = 8
DCE = 4*8 + 15 = 47o