If m <DCE=4x+15 and m<ECF=6X-5 ,find m<DCE
The angles are assumed to be complimentary(sum=90o).
DCE + ECF = 90o
4x+15 + 6x-5 = 90
10x + 10 = 90
10x = 80
X = 8
DCE = 4*8 + 15 = 47o
Álgebra if a supplement of an angle has a measure 78 less than the measure of the angle,what are the measures of the ángeles?