I don't know the formula for calculating the magnitude of the momentum of the earth in its journey around the sun. The mass is 6x10^24kg and its radius of orbit is 1.5x10^11m.

Velo.of earth=1.5x10^11/365x24x3600 m/sec if we take time of revolution as 365 days.

Momentum = mass x velocity. Calculate
1.5x10^11x6x10^24/365x24x3600 kgm
9x10^25/1.151x10^10=7.819x10^16 kgm

To calculate the magnitude of the momentum of the Earth in its journey around the sun, we need to use the formula for momentum:

Momentum (p) = mass (m) x velocity (v)

In this case, the Earth is moving in a circular orbit around the sun, so we can calculate its velocity using the formula for the circumference (C) of a circle:

C = 2πr

Where r is the radius of the orbit. Since the velocity of the Earth is given by the distance it travels divided by the time taken, we can express it as:

v = C / T

Where T is the time taken for the Earth to complete one orbit around the sun. In this case, the time (T) is the period of the Earth's orbit, which is approximately one year.

Now that we have the velocity, we can calculate the magnitude of momentum (p) using the formula mentioned earlier:

p = m x v

Given:
- Mass of Earth (m) = 6 x 10^24 kg
- Radius of orbit (r) = 1.5 x 10^11 m

Let's calculate the magnitude of momentum (p):

Step 1: Calculate the circumference (C) of the Earth's orbit using the formula C = 2πr.
C = 2 x π x 1.5 x 10^11
C ≈ 9.42 x 10^11 m

Step 2: Calculate the velocity (v) of the Earth using the formula v = C / T.
Since T is the time taken for the Earth to complete one orbit around the sun and is approximately one year, we can use T = 365 days.
v = (9.42 x 10^11) / (365 x 24 x 3600)
v ≈ 2.98 x 10^4 m/s

Step 3: Calculate the magnitude of momentum (p) using the formula p = m x v.
p = (6 x 10^24) x (2.98 x 10^4)
p ≈ 1.79 x 10^29 kg·m/s

So, the magnitude of the momentum of the Earth in its journey around the sun is approximately 1.79 x 10^29 kg·m/s.