Trig
posted by Paula .
Given that csc θ = 4 and tan θ > 0, find the exact value of
a. x
b. sin θ
c. cos θ
d. r
e. sec θ
f. cot θ

same as the others ....
cscØ = 4
so sinØ = 1/4
we also know that tanØ>0 so
the sine is negative and the tangent is positive > Ø must be in III
since sinØ = 1/4, in III, y = 1, r = 4
by Pythagoras and the CAST rule
x = √15
The rest is now easy, just use your definitions.
let me know what you get.
e.g.
cotØ = x/y = √15/1 = √15