Pls help me to show that (1+root x)^5= 10 root x + 20x root x + 2x^2 ]oot x.
Using the binomial expansion of
(1+√x)^5
= 1 + 5√x + 10 (√x)^2 + 10 (√x)^3 + 5 (√x)^4
+ √x^5
= 1 + 5√x + 10x + 10x√x + 5x^2 + x^2 √x
so your statement is false
(how did you get that ??)
check with some value of x
e.g. x = 4
(1+√4)^5 = 243
your expression
= 10√4 + 20(4)√4 + 2(16√4
= 20 + 160 + 64 = 244
my answer
= 1 + 5(√4) + 10(4) + 10(4)√4 + 5(16) + 16√4
= 1 + 10 + 40 + 80 + 80 + 32
= 243