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The fraction 5Y3X/2Y8, in which x and Y stand for two unknown digits, represents a division which results in a quotient that is a whole number. Which of the following is (are) true?

1. X may equal 2.
11. X may equal 6 or 0.
111. X may equal 4.

not just and answer, i don't get this question very much.

A.1 only
B.11 only
C.111 only
D.1 and 111 only
E.1,11,and 111

  • math -

    3X5Y/2Y8 = 15x/16.
    15x/16 = 1 = The smallest whole number.
    15x = 16
    X = 16/15 = 1 1/15.

    According to my analysis, x cannot equal
    0,2,4, nor 6.

  • math -

    f y=0 --> 503?/208 = appr 24
    to be exact 24*208 = 4992 , so y ≠ 0
    if y = 1 --> 513?/218 = appr 24
    24*218 = 5232 , so y≠1
    y=2 --> 523?/228 = 23
    23*228 = 5244 , so y≠2
    y=3 --> 533?/238 = appr 22
    22*238 = 5236 , so y≠3
    y = 4 --> 543?/248 = appr 22
    22*248 = 5456 , so y≠4
    y = 5 --> 553?/258 = appr 21
    21*258 = 5418 , so y≠5
    y = 6 --> 563?/268 = appr 21
    21*268 = 5628
    20*268 = 5360 , y ≠ 6

    y = 7 -> 573?/278 = appr 21
    21*278 = 5838
    20*278 = 5560 , y ≠ 7

    y = 8 --> 583?/288 = appr 20
    20*288 = 5760
    21*288 = 6048
    19*288 = 5472 , y ≠ 8
    y = 9 --> 593?/298 = appr 21
    21*298 = 6258
    20*298 = 5960
    22*298 = 6556

    I have exhausted all possible choices for y from 0 to 9
    since x depends on what y values we choose,
    and unless I made an arithmetic error, no values of x and y make the statement true.

  • math -

    I. X may equal 2.
    II. X may equal 6 or 0.
    III. X may equal 4.

    A.I only
    B.II only
    C.III only
    D.I and III only
    E.I,II,and III

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