BaO2(s) + 2 HCl(aq) H2O2(aq) + BaCl2(aq)
What amount of hydrogen peroxide should result when 1.00 g of barium peroxide is treated with 15 mL of hydrochloric acid solution containing 0.0330 g of HCl per mL?
So confused... >.<
This is a limiting reagent problem Working these boils down to doing two problems within the one and using the smaller value. Here is a set of directions that will do all limiting reagent problems. The only difference in this problem is you aren't given grams HCl directly but it is available indirectly; i.e., 15 mL x g/mL = grams.
http://www.jiskha.com/science/chemistry/limiting_reagent_problem.html
To find the amount of hydrogen peroxide that should result from the reaction, we need to calculate the stoichiometry of the reaction. The balanced equation tells us that 1 mole of barium peroxide (BaO2) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of hydrogen peroxide (H2O2) and 1 mole of barium chloride (BaCl2).
First, we need to determine how many moles of barium peroxide we have. We can calculate this by using the molar mass of BaO2.
The molar mass of BaO2 can be calculated by adding the molar masses of one barium atom (Ba) and two oxygen atoms (O).
Ba: 137.33 g/mol
O: 16.00 g/mol
Molar mass of BaO2 = (1 * 137.33 g/mol) + (2 * 16.00 g/mol) = 169.33 g/mol
Next, we can calculate the number of moles of BaO2 using its mass (1.00 g) and the molar mass.
Number of moles of BaO2 = mass / molar mass
= 1.00 g / 169.33 g/mol
= 0.00591 mol
Now, let's determine the number of moles of HCl using its mass and volume.
Mass of HCl = volume of HCl solution * mass of HCl per mL
= 15 mL * 0.0330 g/mL
= 0.495 g
Molar mass of HCl = 1.008 g/mol (H) + 35.453 g/mol (Cl) = 36.461 g/mol
Number of moles of HCl = mass / molar mass
= 0.495 g / 36.461 g/mol
= 0.0136 mol
According to the balanced equation, 1 mole of BaO2 reacts with 2 moles of HCl to produce 1 mole of H2O2. Therefore, the ratio of moles of BaO2 to H2O2 is 1:1.
Since we have 0.00591 mol of BaO2, we should expect to produce 0.00591 mol of H2O2.
Finally, we can calculate the mass of H2O2 using its molar mass.
Molar mass of H2O2 = (2 * 1.008 g/mol (H)) + (2 * 16.00 g/mol (O)) = 34.014 g/mol
Mass of H2O2 = number of moles * molar mass
= 0.00591 mol * 34.014 g/mol
= 0.200 g (rounded to three decimal places)
Therefore, when 1.00 g of BaO2 is treated with 15 mL of hydrochloric acid solution containing 0.0330 g of HCl per mL, we should expect to produce approximately 0.200 g of hydrogen peroxide.