how many moles of Mg2+ and NO3(there is a negative sign on top of the 3 in NO3)form for each mole of Mg(NO3)2 that dissolves?

Mg(NO3)2 ==> Mg^2+ + 2NO3^-

Look at the equation. The equation tells you that you get 1 mol Mg^2+ and 2 mols NO3^- for every 1 mol Mg(NO3)2 that dissolves.

To determine the number of moles of Mg2+ and NO3- ions that form for each mole of Mg(NO3)2 that dissolves, we need to look at the chemical formula of Mg(NO3)2.

The chemical formula of Mg(NO3)2 indicates that there is one magnesium ion (Mg2+) and two nitrate ions (NO3-) present.

Therefore, for each mole of Mg(NO3)2 that dissolves, it will produce one mole of Mg2+ ions and two moles of NO3- ions.

To determine the number of moles of Mg2+ and NO3- ions formed when one mole of Mg(NO3)2 dissolves, we need to consider the dissociation of the compound.

The chemical formula of Mg(NO3)2 suggests that it contains one magnesium ion (Mg2+) and two nitrate ions (NO3-). When an ionic compound like Mg(NO3)2 dissolves in water, it dissociates into its constituent ions.

Therefore, for each mole of Mg(NO3)2 that dissolves, we obtain one mole of Mg2+ ions and two moles of NO3- ions. This is because there is only one magnesium ion and 2 nitrate ions in each formula unit of Mg(NO3)2.

So, the number of moles of Mg2+ ions formed is 1 mole per mole of Mg(NO3)2, and the number of moles of NO3- ions formed is 2 moles per mole of Mg(NO3)2.