A rectangular field has a length that us 2 meters less than 3 times the width. The perimeter is 188 meters. Find the dimensions of the field
P = 2L + 2W
188 = 2(3w - 2) + 2W
188 = 6W - 4 + 2W
188 + 4 = 8W
192/8 = W
24 = W
188 = 2(3w - 2) + 2W
188 = 6W - 4 + 2W
188 + 4 = 8W
192/8 = W
24 = W