when one gram of water solidifies to ice 333.33 j of heat is evolved. calculate enthalpy of fusion of ice?
It's a ridiculous explanation to the question
To calculate the enthalpy of fusion of ice, we need to use the equation:
Enthalpy of fusion = heat evolved / mass of water
Given:
Heat evolved (ΔH) = 333.33 J
Mass of water = 1 g (since we have one gram of water)
Now we can plug in these values into the equation:
Enthalpy of fusion = 333.33 J / 1 g
Calculating the result:
Enthalpy of fusion = 333.33 J/g
Therefore, the enthalpy of fusion of ice is 333.33 J/g.
To calculate the enthalpy of fusion of ice, we need to use the heat evolved and the mass of water that solidified.
The formula for calculating enthalpy of fusion is:
Enthalpy of Fusion = Heat Evolved / Mass of Water
Given:
Heat Evolved (ΔH) = 333.33 J
Mass of Water = 1 gram
Substituting the values into the formula:
Enthalpy of Fusion = 333.33 J / 1 g
To find the enthalpy of fusion in joules per gram (J/g), divide the heat evolved by the mass of water.
Enthalpy of Fusion = 333.33 J / 1 g = 333.33 J/g
Therefore, the enthalpy of fusion of ice is 333.33 J/g.