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It is claimed the average age of employee in a large company is 50. A sample of 36 employees is taken and the average age was 49. The standard deviation of the population was 5. Use a level of significance of .05. What do you think of this claim?

  • statistics -

    Try a one-sample z-test on this data:
    z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

    z = (49 - 50)/(5/√36)

    I'll let you finish the calculation.

    Check a z-table for your critical or cutoff value at .05 level of significance. Compare the test statistic you calculated to the critical value from the table. Draw your conclusions.

    I hope this will help get you started.

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