Post a New Question

physics

posted by .

A diver springs vertically upward with an initial speed of 1.7 m/s from a diving board
that is 3.2 m above the water. Find the speed with which she enters the water, assuming
completely vertical motion.

  • physics -

    mv₀²/2= mgh
    h= v₀²/2g
    mg(H+h) = mv²/2
    mgH +mv₀²/2 = mv²/2
    v=sqrt{ v₀² +gH} =
    = sqrt{1.7²+9.8•3.2} = 5.85 m/s

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question