Question

How many moles of compound are in 30.2 g of Na2CO3·10H2O?

Answer 1

mols = grams/molar mass

Answer 2

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Answer 3

[AI-generated answer — Explain Bot]

To find the number of moles of a compound, we need to use its molar mass.

To calculate the molar mass of Na2CO3·10H2O, we first need to calculate the molar mass of each individual element in the compound.

The molar mass of sodium (Na) is 22.99 g/mol.
The molar mass of carbon (C) is 12.01 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
The molar mass of hydrogen (H) is 1.01 g/mol.

Now, let's calculate the molar mass of Na2CO3·10H2O:

(2 * molar mass of Na) + molar mass of C + (3 * molar mass of O) + (10 * (molar mass of H * 2)) + (molar mass of O * 10)

(2 * 22.99) + 12.01 + (3 * 16.00) + (10 * (1.01 * 2)) + (16.00 * 10)

45.98 + 12.01 + 48.00 + 20.20 + 160.00

The molar mass of Na2CO3·10H2O is 286.14 g/mol.

To find the number of moles, we need to use the formula:

moles = mass / molar mass

Now, let's substitute the given mass:

moles = 30.2 g / 286.14 g/mol

moles = 0.1055 mol

Therefore, there are approximately 0.1055 moles of Na2CO3·10H2O in 30.2 g.