A 15kg object is pushed to the right with a net force of 60N. If a 5kg object experiences the same acceleration, how much force is it being pushed with?
F = m a
When acceleration is equal:
F2 = m2 F1/m1
To solve this problem, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Given:
Mass of the first object (m1) = 15 kg
Net force on the first object (F1) = 60 N
We need to find the force acting on the second object (F2) when it experiences the same acceleration.
Let's assume the acceleration of both objects is the same (a).
According to Newton's second law, we have the following equation for both objects:
F1 = m1 * a
60 N = 15 kg * a
Now, let's calculate the acceleration:
a = 60 N / 15 kg
a = 4 m/s^2
Now, we can find the force on the second object (F2) using the same acceleration (a) and its mass (m2).
Mass of the second object (m2) = 5 kg
Force on the second object (F2) = ?
Using Newton's second law again:
F2 = m2 * a
F2 = 5 kg * 4 m/s^2
F2 = 20 N
Therefore, the second object is being pushed with a force of 20 N.
To find the force acting on the 5kg object, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration: F = m * a.
Let's first find the acceleration of the 15kg object. We can use the equation F = m * a, where F is the net force and m is the mass.
Given:
Net force (F) = 60N
Mass (m) = 15kg
So, F = m * a
60N = 15kg * a
To find the acceleration (a) of the 15kg object, we divide both sides of the equation by the mass (15kg):
60N / 15kg = a
a = 4 m/s^2
Now, we can find the force acting on the 5kg object using the same acceleration. We rearrange the equation F = m * a to solve for force:
F = m * a
Given:
Mass (m) = 5kg
Acceleration (a) = 4 m/s^2
Substituting the values in the equation, we have:
F = 5kg * 4 m/s^2
F = 20N
Therefore, the 5kg object is being pushed with a force of 20N.